Explain how these three situations would change a chip board (regardless of the starting value of the chips on the chip board). EX: "The first situation would cause the chip board to change by..... This would happen because....."
a. Adding 7 red chips and 13 black chips
b. Adding 15 red chips and 15 black chips
c. Adding 24 red chips and 17 black chips
12 comments:
The first situation would cause the chip board to change by positive 6, or increase by 6. This would happen because the equation -7+13 would equal 6. The second situation would not change the chip board at all. This would happen because 15 and -15 are opposites, which equal 0. The third situation would cause the chip board to change by -7, or decrease by 7. This would happen because if you find the absolute value of -24 and subtract 17 from that absolute value, you would get 7. You then have to take the sign of the larger absolute value and give it to the answer, which is negative.
In the first situation the value would gain by 6 black or positive chips. The reason why is because when you make zero pairs there will only be 7 pairs. You could also say 13+
-7= 6. In the second situation the value of the chipboard would not change. The reason why is because all of the re and black chips cancel them out. If you did number sentence it would look like15+ -15=0. In the third situation there would be 4 red or negative left. The reason why is because when you do the zero pairs only 17 of them cancel each other out. So if you were to write a number sentence it would be –24+17=-4.
The first situation would change the value of the chip board by adding 6 positive (black) chips. This is because there are 7 negative chips and 13 positive chips, therefore you cross out 7 negative (red) chips and 7 positive (black) chips because they cancel each other out. Once you do this, you have 6 positive (black) chips left, making the value go up by 6 chips.
The second situation would not change the value of the chip board. Since there are 15 positive AND negative chips, they cancel each other out. This is because you add the same number of both, so it will not make the value of the chips increase or decrease.
The third situation would change the value of the chip board by adding 7 more red (negative) chips. This is because you are adding 24 red (negative) chips and 17 black (positive) chips. So you would cancel 17 of black and red chips, therefore you are just adding 7 more red (negative chips.)
The value of the chip board all depends on how many positive and negative chips you are adding.
In the first instance the board would equal positive 6 the reason being that -7+13=6.
In the second instance the end result would be 0,because 15+-15=0.In the final instance th end result would be -4 this is because 24 red and 17 black would be shown in a number sentence like this -24+17=-4
The first situation would cause the chip board to change by positive 6. This would happen because 13+-7=6. You would cross out, or take away 7 of the chips leaving 6 remaining. In the second situation there would not be any change. -15+15= 0. They would all cancel each other out. The third situation would cause the chip board to change by -7. This would happen because the absolute value of 24 is greater than 17, that is why then answer is negative. You would cross out\take away all 17 with -7 left to equal 24.
The first situation would change the value of the chip board by positive 6. This is because no matter what the value of the chip board before, if you add -7 (7 red chips) and +13 (13 black chips) you can make 7 zero pairs, and so that would cancel out everything but 6 black chips…or +6. You can also conclude that -7+13 equals +6.
The second situation would not change the value of the chip board at all. If you add -15 (15 red chips) and +15 (15 black chips) you could make exactly 15 zero pairs, which would cancel every chip out keeping the value of the chip board the same value as it was before we add those chips. You can also conclude that -15+15 equals 0.
The third situation would change the value of the chip board by a negative 7. This is because no matter what the value of the chip board before, if you add -24 (24 red chips) and +17 (17 black chips) you can make 17 zero pairs, and so that would cancel everything out except for 7 red chips…or -7.
The first situation would have an answer of 6 because you are going to change the situation from 13+-7= to 13-+7=6.
The second situation would have an answer of 0 because you are going to change -15+15= to 15-15=0.
The third situation would have an answer of -7 because you are going to change -24+17= to -24-17= -7. The value of each chip board depends on how many positive and negative chips you are adding.
Situation A would cause the chip board’s value to increase. The 13 black chips and 7 red chips would cause the value to increase by 6. Black chips are positive numbers and red chips are negative numbers. One way you can remember this is when you are working with chips, think of pennies. When you are adding black chips to the chip board, you are depositing money into your bank account and when you are adding red chips, you are depositing money into your bank account.
Situation B would not change the value of the chip board, because 15 and -15 cancel each other out, they are absolute values. The chip board would not be affected, there would only be more chips on the board.
Situation C would cause the chip board’s value to decrease by 7. Remember that the red chips are negative, so the 17 black chips would be subtracted from the 24 red chips. The number with the greater value will be the sign that the answer will have.
The first situation would cause the chip board to change by 6 red chips because 7-13=-6 and this would happen because +6+-13 would equal -6. The second situation would cause the chip board to change by nothing because 15+-15 equals 0 so the chips would zero each other out. The third and final situation would cause the chip board to change by 7 black chips. This would happen because 24+-17=7 so that is why it would change by positive seven.
The value of the chip board depends on how many positive and negative chips you are adding to it.
In the first situation the value of the chip board by adding 6 positive chips. There were 7 negative (red) and 13 positive (black), you have more positive chips then negative so you know the number will be positive. You have to take away 7 black and 7 red to make 7 zero pairs. Or you could solve the equation, -7+13=?
In the second situation the value of the chip board would not change. There are 15 red and 15 black so you would have 15 zero pairs.
The third situation would change the value of the chip board by adding 7 more negative chips. This is because you are adding 24 negative chips and 17 positive chips. You would cancel 17 positive chips and 17 negative chips and have 17 zero pairs.
Love Carlisle Hatton your favorite student of all times:) <3
In the first situation, adding 7 “negative” red chips and 13 “positive” black chips places 6 “positive” black chips on the board. This would increase the number of chips on the board by “positive” 6 black chips. This would happen because when adding 7 “negative” red chips and 13 “positive” black chips together, the 7 “negative” red chips cancel out 7 “positive” black chips. When these chips are cancelled out, the sum of -7+13 equals +6.
In the second situation, adding 15 “negative” red chips and 15 “positive” black chips causes the value of the chips on the board to remain the same. This would happen because the 15 “negative” red chips and the 15 “positive” black chips cancel each other out completely, causing the value of the chip board to remain exactly as it was before.
In the third situation, adding 24 “negative” red chips and 17 “positive” black chips, leaves 7 “negative” chips on the board. There are 7 “negative” red chips left because the 17 “positive” black chips and the 17 “negative” red chips cancel each other out. This leaves the 7 “negative” red chips on the board.
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